What is the quantity, in moles, of KBr present in 60.0 mL of a 0.150 M KBr solution?

• A. 0.0600 mol
• B. 0.150 mol
• C. 0.00400 mol
• D. 0.00900 mol

Answer: (D)

Verified step by step guidance

1. Identify the given information: the volume of the KBr solution is 60.0 mL and the molarity (M) of the solution is 0.150 M. Molarity is defined as moles of solute per liter of solution.
2. Convert the volume from milliliters to liters because molarity uses liters as the volume unit. Use the conversion factor: \$1\, \text{L} = 1000\, \text{mL}\(. So, \)60.0\, \text{mL} = \frac{60.0}{1000}\, \text{L}$.
3. Use the molarity formula to find the number of moles of KBr: \(\text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}\). Rearranged, this becomes \(\text{moles of solute} = \text{Molarity} \times \text{liters of solution}\).
4. Substitute the known values into the equation: \(\text{moles of KBr} = 0.150\, \text{mol/L} \times \text{volume in liters}\) (from step 2).
5. Calculate the product to find the number of moles of KBr present in the solution.