What is the molarity of a solution prepared by dissolving 52.0 g of glucose (C6H12O6) in enough water to make 0.750 L of solution?

• A. 0.384 M
• B. 0.512 M
• C. 1.15 M
• D. 0.114 M

Answer: (A)

Verified step by step guidance

1. Identify the formula for molarity, which is the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
2. Calculate the molar mass of glucose (C6H12O6) by summing the atomic masses of all atoms: \$6 \times 12.01 + 12 \times 1.008 + 6 \times 16.00$ g/mol.
3. Convert the given mass of glucose (52.0 g) to moles using the molar mass: \(\text{moles} = \frac{52.0 \text{ g}}{\text{molar mass of glucose}}\).
4. Use the volume of the solution given (0.750 L) directly in the molarity formula.
5. Calculate the molarity by dividing the moles of glucose by the volume of the solution in liters: \(M = \frac{\text{moles of glucose}}{0.750}\).