What is the mass (in grams) of 10.00 L of propane vapor (C3H8) at standard temperature and pressure (STP)?

• A. 44.0 g
• B. 10.0 g
• C. 22.4 g
• D. 19.8 g

Answer: (D)

Verified step by step guidance

1. Identify the given information: volume of propane vapor (V) = 10.00 L, and conditions are at standard temperature and pressure (STP). At STP, 1 mole of any ideal gas occupies 22.4 L.
2. Calculate the number of moles of propane gas using the molar volume at STP with the formula: \(n = \frac{V}{22.4\ \text{L/mol}}\).
3. Determine the molar mass of propane (C\_3H\_8) by summing the atomic masses: Carbon (C) = 12.0 g/mol, Hydrogen (H) = 1.0 g/mol, so molar mass = \$3 \times 12.0 + 8 \times 1.0$ g/mol.
4. Calculate the mass of propane using the formula: \(\text{mass} = n \times \text{molar mass}\), where \(n\) is the number of moles found in step 2.
5. Express the final answer in grams, which represents the mass of 10.00 L of propane vapor at STP.