Multiple Choice
What is the molarity of a solution prepared by dissolving 10.7 g of NaI in 0.250 L of solution? (Molar mass of NaI = 149.89 g/mol)
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6. Chemical Quantities & Aqueous Reactions
Molarity
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What is the concentration of lithium ions in a 0.350 M solution of Li\(_3\)PO\(_4\)?
A
1.05 M
B
0.700 M
C
0.350 M
D
0.117 M
Verified step by step guidance1
Identify the chemical formula of the compound: Li\(_3\)PO\(_4\) contains lithium ions (Li\(^+\)) and phosphate ions (PO\(_4^{3-}\)).
Determine the number of lithium ions produced per formula unit of Li\(_3\)PO\(_4\). Since there are 3 lithium atoms in the formula, each formula unit dissociates into 3 Li\(^+\) ions.
Write the dissociation equation for Li\(_3\)PO\(_4\) in water: \(\mathrm{Li_3PO_4 (s) \rightarrow 3 Li^+ (aq) + PO_4^{3-} (aq)}\).
Calculate the concentration of lithium ions by multiplying the molarity of the Li\(_3\)PO\(_4\) solution by the number of lithium ions per formula unit: \([\mathrm{Li^+}] = 3 \times 0.350\ \mathrm{M}\).
Express the final concentration of lithium ions in molarity (M), which represents the total concentration of Li\(^+\) ions in the solution.
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