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Multiple Choice
Hexane (C6H14) combusts according to the equation: 2 C6H14 + 19 O2 → 12 CO2 + 14 H2O. How many moles of hexane (C6H14) must burn to produce 18.4 mol of carbon dioxide (CO2)?
A
9.20 mol
B
6.13 mol
C
1.53 mol
D
3.07 mol
Verified step by step guidance
1
Identify the balanced chemical equation for the combustion of hexane: 2 C6H14 + 19 O2 → 12 CO2 + 14 H2O.
Note the mole ratio between hexane (C6H14) and carbon dioxide (CO2) from the balanced equation. For every 2 moles of C6H14 burned, 12 moles of CO2 are produced.
Set up a proportion to find the moles of hexane needed to produce 18.4 moles of CO2 using the mole ratio: (2 moles C6H14 / 12 moles CO2) = (x moles C6H14 / 18.4 moles CO2).
Solve the proportion for x, which represents the moles of hexane required: x = (2 / 12) × 18.4.
Interpret the result as the number of moles of hexane that must burn to produce 18.4 moles of CO2.