A 25.0-mL sample of a 1.20 M potassium chloride solution is
mixed...

Question

A 25.0-mL sample of a 1.20 M potassium chloride solution is
mixed with 15.0 mL of a 0.900 M lead(II) nitrate solution and
this precipitation reaction occurs:
2 KCl(aq) + Pb(NO3)2(aq)¡ PbCl2(s) + 2 KNO3(aq)
The solid PbCl2 is collected, dried, and found to have a mass of
2.45 g. Determine the the percent yield.

Accepted Answer

Hi everyone. So we have 20 ml of 0.75 moller a silver carbonate solution reacting with 50, 1.35 molar of sodium bromide. And we're asked calculate the percent yield of % 3.64 g of solid silver bromide precipitate is obtained recall that clarity. It was malls. I saw you divided by leaders solution. We need to first make sure that the equation is balanced. So we're gonna have silver carbonate Plus two sodium bromine. It's gonna yield to silver bromine plus sodium carbonate. And now to find the limiting reagent, we need to calculate the mass of silver bromide produce from each reactant. So we need to convert our volume from male leaders. two leaders. They're gonna have 20 ml. We have 1000 Male leaders in one leader This gives us 0.02 leaders. And we have 0.02 leaders. um 0.75 malls of silver carbonate. In one leader We have one mole of silver carbonate and two malls of silver bromine. And in one bowl a silver bromine have the molar mass which is gonna be a massive silver .868 g plus a massive bro. Mean Which is 79.90 four g. And this gave us 187 .772g. And it's given us 5.63 grams a silver bromine. And then we have 50 million years. We need to convert it to leaders. So we have 1000 male leaders and one leader This give us 0.05 leaders, 0.05 leaders. That was 1.35 balls. Study and bromine. And one leader. We have two malls. So um bromine into malls of silver bromine. And in one mold of silver bromine We have the Mueller mass, which is 187.772 grams. Give us 12.67 grams. So our limiting reagent, it's gonna be silver carbonate because silver carbonate produces a lesser amount of silver bromine. And for our percent yield is equal to the actual yield. Bye bye. Theoretical Times 100%. 5% yield Equals 3.64 grams. got about 5.63 grams times 100 7% yield. Well 64 .65%. Thanks for watching my video and I hope it was helpful.

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