A solution is made by mixing 1.5 g of LiOH and 23.5 mL of
1.000 M...

Question

A solution is made by mixing 1.5 g of LiOH and 23.5 mL of
1.000 M HNO3. (c) Is the resulting solution acidic or basic?

Accepted Answer

Hi everyone here, we have a question asking is the following solution acidic or basic. And it tells us that a solution is made by mixing 2.43 g of acetic acid, ch three C 00 H and 25.0 mL of 1.43 moller sodium hydroxide solution. So first we need to find the moles of each. So we'll start off with acetic acid And it has 2.43 g. We're going to multiply that by one mole Divided by its Molar Mass, which is 60.05. Our g here are going to cancel out, leaving us with zero 0. 05 moles. And now we're going to do the same with sodium hydroxide. But sodium hydroxide, we have milliliters and molar charity. So we're going to start off with our 25.0 ml. And we're going to first change that to leaders. So 10 to the negative. Three leaders over one millimeter Times 1.43 moles over one liter. Because polarity is moles over leader. So our middle leaders are canceling out here and our leaders are canceling out here And that leaves us with 0. 358 moles. Now let's write out the reaction we have. So we have acetic acid plus sodium hydroxide forming sodium acetate and water. So this is already balanced. So our multiple ratio is 1-1. So we have one mole of sodium hydroxide reacting with one mole of acetic acid. So the moles of acetic acid is greater than the moles, sodium hydroxide, meaning that it is the accessory agent and therefore the solution will be acidic. And that is our final answer. Thank you for watching. Bye.

A solution is made by mixing 1.5 g of LiOH and 23.5 mL of 1.000 M HNO3. (c) Is the resulting solution acidic or basic?

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