Given a 0.125 g sample of copper(II) sulfate (CuSO4), how many moles of CuSO4 are present? (Molar mass of CuSO4 = 159.6 g/mol)

• A. 7.84 × 10^{-4} mol
• B. 1.25 × 10^{-3} mol
• C. 0.080 mol
• D. 1.60 × 10^{-2} mol

Answer: (A)

Verified step by step guidance

1. Identify the given information: the mass of copper(II) sulfate (CuSO4) is 0.125 g, and the molar mass of CuSO4 is 159.6 g/mol.
2. Recall the formula to calculate moles from mass and molar mass: \(\text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}\).
3. Substitute the given values into the formula: \(\text{moles of CuSO4} = \frac{0.125}{159.6}\).
4. Perform the division to find the number of moles (do not calculate the final value here, just set up the expression).
5. Interpret the result as the amount of substance in moles present in the 0.125 g sample of CuSO4.