What mass (in grams) of fructose (C6H12O6) is present in 125 mL of a 0.500 mol/L fructose solution?

• A. 3.75 g
• B. 7.50 g
• C. 11.3 g
• D. 22.5 g

Answer: (C)

Verified step by step guidance

1. Identify the given information: the volume of the solution is 125 mL, and the molarity (concentration) of fructose is 0.500 mol/L.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \$1\, \text{L} = 1000\, \text{mL}\(, so \)V = \frac{125}{1000} = 0.125\, \text{L}$.
3. Calculate the number of moles of fructose in the solution using the formula for molarity: \(n = M \times V\), where \(n\) is moles, \(M\) is molarity, and \(V\) is volume in liters.
4. Determine the molar mass of fructose (C\(_6\)H\(_{12}\)O\(_6\)) by summing the atomic masses of all atoms: \$6 \times\( atomic mass of C + \)12 \times\( atomic mass of H + \)6 \times$ atomic mass of O.
5. Calculate the mass of fructose by multiplying the number of moles by the molar mass: \(\text{mass} = n \times \text{molar mass}\). This will give the mass in grams.