How many moles of water (H2O) are present in 75.0 g of H2O?

• A. 1.25 mol
• B. 2.08 mol
• C. 4.17 mol
• D. 0.75 mol

Answer: (C)

Verified step by step guidance

1. Identify the given quantity: 75.0 grams of water (H\_2O).
2. Calculate the molar mass of water by adding the atomic masses of its elements: hydrogen (H) and oxygen (O). The molar mass of H\_2O is calculated as \$2 \times 1.008 + 16.00$ g/mol.
3. Use the formula to convert grams to moles: \(\text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}\).
4. Substitute the given mass and the calculated molar mass into the formula: \(\text{moles of H\_2O} = \frac{75.0}{\text{molar mass of H\_2O}}\).
5. Perform the division to find the number of moles of water present in 75.0 g.