How many moles of nitrogen atoms (N) are present in 0.203 g of N_2O?

• A. 0.0138 moles
• B. 0.00461 moles
• C. 0.00690 moles
• D. 0.0203 moles

Answer: (A)

Verified step by step guidance

1. Identify the chemical formula of the compound, which is N\_2O, meaning each molecule contains 2 nitrogen atoms and 1 oxygen atom.
2. Calculate the molar mass of N\_2O by summing the atomic masses: 2 times the atomic mass of nitrogen (approximately 14.01 g/mol) plus 1 times the atomic mass of oxygen (approximately 16.00 g/mol). The formula is: \(\text{Molar mass of N\_2O} = 2 \times 14.01 + 16.00\) g/mol.
3. Determine the number of moles of N\_2O in 0.203 g by dividing the given mass by the molar mass calculated in the previous step: \(\text{moles of N\_2O} = \frac{0.203}{\text{molar mass of N\_2O}}\).
4. Since each mole of N\_2O contains 2 moles of nitrogen atoms, multiply the moles of N\_2O by 2 to find the moles of nitrogen atoms: \(\text{moles of N atoms} = 2 \times \text{moles of N\_2O}\).
5. The result from the previous step gives the number of moles of nitrogen atoms present in 0.203 g of N\_2O.