How many moles of nitrogen atoms (N) are present in 0.207 g of N_2O?

• A. 0.00929 mol
• B. 0.0141 mol
• C. 0.00652 mol
• D. 0.00470 mol

Answer: (B)

Verified step by step guidance

1. Identify the molecular formula of the compound, which is \(\mathrm{N_2O}\). This means each molecule contains 2 nitrogen atoms and 1 oxygen atom.
2. Calculate the molar mass of \(\mathrm{N_2O}\) by adding the atomic masses of its atoms: \$2 \times\( atomic mass of nitrogen (approximately 14.01 g/mol) plus 1 \)\times\( atomic mass of oxygen (approximately 16.00 g/mol). The formula is: \)\mathrm{Molar\ mass} = 2 \times 14.01 + 16.00$ g/mol.
3. Determine the number of moles of \(\mathrm{N_2O}\) in 0.207 g by using the formula: \(\mathrm{moles\ of\ N_2O} = \frac{\mathrm{mass\ of\ sample}}{\mathrm{molar\ mass}} = \frac{0.207}{\mathrm{molar\ mass}}\).
4. Since each mole of \(\mathrm{N_2O}\) contains 2 moles of nitrogen atoms, multiply the moles of \(\mathrm{N_2O}\) by 2 to find the moles of nitrogen atoms: \(\mathrm{moles\ of\ N} = 2 \times \mathrm{moles\ of\ N_2O}\).
5. The result from the previous step gives the total moles of nitrogen atoms present in 0.207 g of \(\mathrm{N_2O}\).