One way to measure ionization energies is ultraviolet photoelectr...

Question

One way to measure ionization energies is ultraviolet photoelectron
spectroscopy (PES), a technique based on the
photoelectric effect. (Section 6.2) In PES, monochromatic
light is directed onto a sample, causing electrons to
be emitted. The kinetic energy of the emitted electrons is
measured. The difference between the energy of the photons
and the kinetic energy of the electrons corresponds to the
energy needed to remove the electrons (that is, the ionization
energy). Suppose that a PES experiment is performed
in which mercury vapor is irradiated with ultraviolet light
of wavelength 58.4 nm. (d) Using Figure 7.10, determine which of the halogen 
elements has a first ionization energy closest to that 
of mercury.

Accepted Answer

Hi everyone. This problem reads ultraviolet photoelectron spectroscopy. Pes a method based on the photo electric effect is used to measure ionization energies, electrons are emitted by illuminating monochromatic light onto a sample. Then the kinetic energy of the emitted electrons is measured. The ionization energy is the difference between the energy of the photons and the kinetic energy of the electrons assume that a PS experiment is conducted in which xenon gas is illuminated with 100 and 2.3 nanometers identify the halogen whose initial ionization energy is closest to xenon and were given the ionization energies of a couple of halogen. Alright, so our goal here is to identify the halogen which or whose initial ionization energy is closest to xenon. Alright, so in this problem we're dealing with wavelengths, we're dealing with photons photo electrons and so what we're going to need to do here is think about the relationship between the energy of a photon and the wavelength of light. Okay, and there is an inverse relationship that is described by the following equation. Okay, and that equation is energy is equal to Planck's constant, times the speed of light over wavelength. And what this equation is going to tell us is energy in jewels per photon. Alright, that's the first thing we're going to need to do is calculate the energy and we'll take a look at what we have based off of what's given in the problem. All right. So h represents plank's constant. And this is a value We should know which is 6.626 times 10 to the negative 34 jewels times seconds C is the speed of light which is also another value we should know which is 3.0 times 10 to the eighth meters per second. And lambda represents way wavelength. And then the problem we're told that the wavelength is 102.3 nanometers. But something that's important is we need to make sure our units match and they're consistent. So if we look at our speed of light, the unit is in meters. And so that means we're going to need to convert our wavelength from nanometers two m. So let's go ahead and do that In one nanometer, there is 10 to the -9 m. Okay. And so we'll see here that are nanometers cancel and we're left with meters. And so once we do that we get 1.23 times 10 to the negative seven m is our wavelength converted. So now that we have all the values, let's go ahead and calculate our energy. Okay, so once we plug everything in we'll go ahead and solve so we know what is our energy and jewels per photon. Okay. Mhm. Alright, so now we have everything we need and so we get our energy is 1.9431 times 10 to the negative 18. Let's clear that up a little bit times 10 to the negative jules per photon. So in one photon this is our energy. Okay, so now we want to identify the halogen, whose initial ionization energy is closest to zenon. And as we can see here our units for ionization energy are in kila jewels per mole. So what that means here is we want to go from jewels or let's write it in a different color. We want to go from jewels per photon, two kila jules Permal. This is our goal. So let's go ahead and start off with what we just calculated. So we have 1.9431 times to the negative 18 jewel per photon. So first we can go we know we need to be in kill a jewel. So we can go from jewels to kill a jules first. Alright, so in one kill a jewel There is 1000 jewels and we'll make sure our units cancel. So our jewels cancel. And now we're in killer jewels. Next we want to go from photon two moles. And remember all the God rose number here and one mole. There is 6. There's 6.022 times 10 to the 23 photons. Okay and again that is over. God rose number. So our photons cancel. And now we're left with killer joules per mole which is what we wanted. All right, so once we do this math, we get 1,170. Kill it jules per mole. And the question is asking us to identify the halogen whose initial ionization energy is closest to xenon. Okay, so looking at the answer choices given which one is closest to 1170.1. Okay. The closest is going to be bro ming. Alright, so browning at 1140 kila jewels per mole is going to be the correct answer. Alright, so that is it for this problem. I hope this was helpful.

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