A solution of nitric acid (HNO3) has a molarity of 3.539 M. If the solution contains 3.539 moles of HNO3 in 1.00 L and the mass of the solution is 1.25 kg, what is the density of the solution in g/mL?

• A. 1.25 g/mL
• B. 2.83 g/mL
• C. 0.80 g/mL
• D. 1.00 g/mL

Answer: (A)

Verified step by step guidance

1. Identify the given information: the solution contains 3.539 moles of HNO3 in 1.00 L of solution, and the total mass of the solution is 1.25 kg.
2. Recall that density (\rho) is defined as mass divided by volume, expressed as \(\rho = \frac{\text{mass}}{\text{volume}}\).
3. Convert the mass of the solution from kilograms to grams because density is typically expressed in g/mL. Use the conversion: 1 kg = 1000 g.
4. Convert the volume of the solution from liters to milliliters since density units are g/mL. Use the conversion: 1 L = 1000 mL.
5. Calculate the density by dividing the mass in grams by the volume in milliliters using the formula \(\rho = \frac{\text{mass (g)}}{\text{volume (mL)}}\).