Determine the energy, in joules per photon, of radiation with a frequency of 8.52 × 10^15 s⁻¹.

• A. 1.28 × 10^-17 J
• B. 5.65 × 10^-18 J
• C. 7.12 × 10^-20 J
• D. 3.40 × 10^-19 J

Answer: (B)

Verified step by step guidance

1. Start by recalling the formula for the energy of a photon, which is given by the equation: $E=h\nu$, where $E$ is the energy of the photon, $h$ is Planck's constant, and $\nu$ is the frequency of the radiation.
2. Planck's constant ($h$) is a fundamental constant in physics with a value of approximately $6.626\times 10⁻34J\cdot s$.
3. Substitute the given frequency of the radiation, $8.52\times 10¹⁵s⁻1$, into the formula: $E=6.626\times 10⁻34J\cdot s\times 8.52\times 10¹⁵s⁻1$.
4. Perform the multiplication of the constants and the frequency to find the energy of the photon. This involves multiplying the numerical values and adding the exponents of 10.
5. Ensure the final result is expressed in joules per photon, which is the standard unit for energy in this context.