The propane fuel (C3H8) used in gas barbeques burns according
to ...

Question

The propane fuel (C3H8) used in gas barbeques burns according
to the thermochemical equation:
C3H8( g) + 5 O2( g)¡3 CO2( g) + 4 H2O( g)
ΔH °rxn = -2044 kJ
If a pork roast must absorb 1.6 * 103 kJ to fully cook, and if only
10% of the heat produced by the barbeque is actually absorbed
by the roast, what mass of CO2 is emitted into the atmosphere
during the grilling of the pork roast?

Accepted Answer

Hey everyone. Our question here is telling us that we have a certain piece of steak and it needs to absorb 539 kg jewels to fully cook And they want us to calculate the mass of carbon dioxide emitted if only 15% of the heat produces actually absorb. So for this question we know that we have 539 kg jules needed to fully cook our steak. But since they only want to calculate 15% of the heat produced, We can go ahead and divide our 539 killed jules by 0.15, Which is our 15%. So using this to answer our question, we can go ahead and use dimensional analysis. So starting off with 15% of 539 killed Jules, we can go ahead and use our standard entropy of our reaction, which is 5756.6 kg jewels. And the key to this question is to recognize that this is per eight mole of carbon dioxide. Since we've produced eight moles of carbon dioxide in our reaction. And to convert from moles of carbon dioxide into grams of carbon dioxide, we can go ahead and use our molar mass, Which is 44.01 g per mole. And when we calculate this out, we end up with a value of 219. g of carbon dioxide, which we can further simplify too 2.2 times 10 squared grams of carbon dioxide to match our sig figs. And this is going to be our final answer. So I hope this made sense and let us know if you have any questions.

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