For a given type of MO, use a s2s as an example, is the
bonding ...

Question

For a given type of MO, use a s2s as an example, is the 
bonding or antibonding orbital higher in energy? Explain.

Accepted Answer

Hello everyone today. You have the following problem. Consider a Pi two P orbital For a certain type of molecular orbital diagram justify whether the bonding orbital or the anti bonding orbital will have a higher energy justify your answer. So when it comes to a two p orbital we have two types of combinations. We have an additive combination and we also have a subtracted combination. Now another word for additive combination is bonding molecular orbital. So bonding M. O. And subtracted would be the opposite, which would be our anti bonding molecular orbital or M. O. And so in an additive combination, the bonding orbital's actually have lower energies. So they have lower energies than the isolated toupee orbital's then isolated to p orbital's. And so this indicates that there will be increased electron density Between the two atoms. As you can imagine the opposite is said for are subtracted the anti bonding orbital's where there's no overlap, have higher energies then the isolated to p orbital's and as a result the electron densities will be much lower Between the two atoms. So when you have bonding occurring, you have stability versus when you have non bonding happening or anti bonding, you're going to have a decrease in your stability. And so what the answer choices presented answer choice. D best answer to their question. The anti bonding molecular orbital will have higher energy due to the subtracted combination of the 22 p orbital's. But that we've answered the question overall, I hope that this helped and until next time

Watch next