Using data from Table 13.3, calculate the freezing and boiling po...

Question

Using data from Table 13.3, calculate the freezing and boiling points of each of the following solutions: (b) 0.240 mol of naphthalene 1C10H82 in 2.45 mol of chloroform, g glucose 1C6H12O62 in 188 g of water.

Accepted Answer

Hello everyone today, we are being asked to determine the freezing and boiling points Of a solution composed of 10 g of sucrose dissolved in 250 g of water. So the first thing you want to do is we want to determine the morality that we're working with. And morality can be expressed as morality is equal to our We have 10 g and we are going to have to Multiply that by our Mueller mass of our sucrose or a compound which in this case is 342.3 g per mole. And they were going to multiply by our weight or a mass which is 250 g. But when we convert it to kg by using our conversion factor of We can say that one g is 10 to the negative third kg to give us 0.25 kg. Once we do that, we get a morality value of 0.117, we're gonna know that with em for units and now we can determine the freezing point. So we can say the freezing point noted by F. P is going to be our total change in our temperature. So you go to our KF or our constant times our morality. And so that would look like The 1. degrees of Celsius over em multiplied by the morality that we just found, which is 0.117 morality. And that would give us a temperature of 0.22 degrees Celsius. And so in finding our T F RR temperature, we're going to take the freezing point of water. And we're going to say that zero degrees Celsius and subtract that from our delta T. 0.22 degrees Celsius and get -0.22°C for our freezing point. We're gonna go and highlight that and then boiling point. We're going to go ahead and a note by BP it's gonna be a very similar process. We're going to say our total boiling point elevation is going to be equal to our KB. Or our constant times our morality and that's going to look very similar. But instead the boiling point constant is going to be 0.513 degrees Celsius over m times the morality that we sold 4. modalities that gives us 0.6 degrees Celsius. And then solving for T. B. We have to take our boiling point of water which is 100 degrees Celsius. And we have our our boiling point of sucrose. Excuse me. And we add our Delta T. B. Which is .06°C. and we get an answer of 400.06°C. That's our final answer. I hope this helped. And until next time

Using data from Table 13.3, calculate the freezing and boiling points of each of the following solutions: (b) 0.240 mol of naphthalene 1C10H82 in 2.45 mol of chloroform, g glucose 1C6H12O62 in 188 g of water.

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