What is the molar mass of Al(NO3)3?

• A. 189.99 g/mol
• B. 213.00 g/mol
• C. 242.00 g/mol
• D. 101.96 g/mol

Answer: (B)

Verified step by step guidance

1. Identify the chemical formula of the compound: Al(NO3)3, which consists of 1 aluminum (Al) atom and 3 nitrate (NO3) groups.
2. Determine the atomic masses of each element involved using the periodic table: Aluminum (Al) ≈ 26.98 g/mol, Nitrogen (N) ≈ 14.01 g/mol, Oxygen (O) ≈ 16.00 g/mol.
3. Calculate the molar mass of one nitrate ion (NO3) by adding the atomic masses: 1 nitrogen atom + 3 oxygen atoms, which is \$14.01 + 3 \times 16.00$ g/mol.
4. Multiply the molar mass of the nitrate ion by 3 because there are three nitrate groups in the formula: \$3 \times (14.01 + 3 \times 16.00)$ g/mol.
5. Add the molar mass of aluminum to the total molar mass of the three nitrate ions to get the molar mass of Al(NO3)3: \$26.98 + 3 \times (14.01 + 3 \times 16.00)$ g/mol.