Which of the substances CdBr2, P4, BrF3, MgO, NF3, BaCl2, POCl3, ...

Question

Which of the substances CdBr2, P4, BrF3, MgO, NF3, BaCl2, POCl3, and LiBr contain bonds that are:
(b) nonpolar covalent?

Accepted Answer

well everyone's on this video taking a look at these six different substances and we're being asked which one has a non polar covalin bond. So we can determine this by looking at the electro negativity difference of these different atoms. So starting off with our c. d. f. two, so delta and so delta stands for the difference of and then Ian just simplified for ultra negativity. So these values can be either found in your textbook, given to you by professor or even found online. These are just values that I have. So starting off with the flooring we have value of four and cadmium has a value of 1.7. So the difference of those two is equal to 2.3. Next is N four because it only has one type of bond and they're both the same atom. The difference, no matter what the value is, is equal to zero. Then we have I cl three. So chlorine has a value of three and iodine has a value of 2.5. So three minus 2.5 is equal to 0.5. Next is S. R. O. So auction has a value of 3.25 and S. R. has a value of 1.0. The difference of those two is 2.5. So we're just doing the same thing over and over here. Next is O. F. Two. So florian has the value of again four and oxygen has a value of 3.5. So the value of those two are between those two is 0.5. And lastly is N a c e L, so chlorine has a value of three, and sodium has a value of 0.9. So the electro negativity difference of those two is equal to 2.1. So we can see now out of all these six different substances, the only substance that has a non polar covalin bond is going to be b r n four.

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