According to the aufbau principle, which orbital is filled immedi...

Question

According to the aufbau principle, which orbital is filled immediately after each of the following in a multielectron atom?
(a) 4s 
(b) 3d
(c) 5f
(d) 5p

Accepted Answer

Hello everyone today. We have the following problem. Following the off ball principle, identify the orbital filled after the orbital's listed below. So the off ball principle is a set of how each of these or how orbital's are usually filled in a with electrons. And so we start off with our one s orbital followed by a two S. Three s. We go down until we hit our eight s orbital. We skipped the one s. But next door to us we're going straight to P three P. Four P. All the way down six p. 7 p. There is no eight p. For the third row next to the three P. We then write our three D. Followed by four D. Five D. And six D. Next to our four D. We write four F. And lastly five F. So as part of our Diagram, the way that our electrons are filling these orbital's, it starts with R. one s. And they were just gonna draw an arrow diagonally from each outside orbital. So there's three P. To the four S three D. 25 s. We're gonna have four D. 26 S. Four F. 27 S. And then five F. 28 S. And this is the order we're gonna label this as our half bar diagram. And so in answering our question, we're gonna start with one, We have our three p. And according to our off ball diagram after three P. We're going to fill our four s orbital for our second problem, we have four F. Once again, according to our diagram after that we fill our five D. For our third problem. We have to s. After two S, we moved to two P and last, but not least with our last problem. Five D. After five D, we fill our six P orbital. And so this is going to completely answer our question using the off bar diagram. Overall, I hope that this helped, and until next time.

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