The reaction between ethyl iodide and hydroxide ion in
ethanol 1C...

Question

The reaction between ethyl iodide and hydroxide ion in
ethanol 1C2H5OH2 solution, C2H5I1alc2 + OH- 1alc2 ¡
C2H5OH1l2 + I - 1alc2, has an activation energy of
86.8 kJ>mol and a frequency factor of 2.10 * 1011 M-1 s-1.
(d) Assuming the frequency factor and activation
energy do not change as a function of temperature,
calculate the rate constant for the reaction at 50 C.

Accepted Answer

hi everyone for this problem, it reads ethanol can be dehydrated over alumina catalyst to yield ethylene and water. The activation energy and the frequency factor for the reaction are 26. kg per mole and three times 8 to 10 to the eighth seconds inverse, respectively, calculate the rate constant for the reaction at 75 degrees Celsius assume that the activation energy and the frequency factor do not change with temperature. Okay, so our goal here is to calculate the rate constant for the reaction At 75°C. And we can calculate the rate constant using the Iranians equation. And that equation is Ln of K is equal to A times E raise to negative activation energy over R. T. Okay, so let's just write in what we know based off of what was given in the problem. So we know what A is a is our Frequency factor and we're told it is 3.00 times 10 To the 8th seconds Inverse. Our activation energy was also given that is 26.6 killer jewels per mole. Our is our constant and it is a value. We should have memorized that is 8.314 jewels over Mul Times Kelvin. And our temperature is 75°C. So let's just take a look at our units here to make sure everything matches for our our we have our energy and jewels and our temperature in Kelvin. So that means we need to convert our activation energy to jewels and in one kill a jewel We have 1000 jewels. So that means our activation energy and jules is going to be 26, jewels per mole. And for a temperature we need to go from C to Kelvin and we can do that by adding 273.15. So that's going to give us the temperature in Kelvin of 348.15 Kelvin. Okay, so now we have everything that we need to plug into our equation above to solve for this problem. So let's go ahead and do that. So we have L N. F K is equal to a which is 3.0 times 10 to the eighth seconds, inverse times E raised to negative activation energy. So negative 26, jules Permal over our 8.314 jewels over more times kelvin times temperature 348.15 kelvin. Okay, so if we simplify this a little bit, we'll get Ln of K is equal to 3. times 10 To the 8th seconds, Inverse times E raised to the negative 9.19. Okay, so moving from here when we saw this out by raising um the E to the negative 9.19. That's going to cancel out the L N. Okay, and so this L N is going to cancel here because we have the race to Okay, so then we're going to get a final answer of K, Which is our rate constant. K is equal to 3.06 times 10 to the fourth seconds inverse. Okay, so 3.06 times 10 to the 4th, 2nd inverse is our rate constant. And that is the answer to this problem, and that is the end of this problem. I hope this was helpful.

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