For each compound,
1. name the functional group.

Question

For each compound,

1. name the functional group.

2. show what compound(s) result from complete hydrolysis.

(a)

Accepted Answer

Hey everyone and welcome back name the functional group present in the following compounds and show the products of their complete hydraulics. Is now looking at the structure. It's really important to notice this carbon atom that is bonded to two elk oxy groups. Right? You have to like oxy group, there's our meth oxy group on the left, another meth oxy group on the right, there are two alcohol groups. So if you recall whenever we have to al Toxie groups or basically O. R one OR two, Let's suppose. Here we have two alcohol groups, R three and R four. This structure is called a saddle. Note that you definitely don't want to confuse it with hemi a saddle where you're replacing one of your ilk oxy groups with an alcohol group. So be very careful whenever you have two Alcock see groups that societal one Alcock C group, the other one is alcohol. That will be hemi a saddle. But in this case because there are two Alcock see groups, right? We have these two meth oxy groups. That's an acid L. So we can say that this would be our first answer to this problem, we can name this functional group as an S. Model. Now we want to draw the products of the complete hydraulic assist of this snL. So let's see that first of all, let's draw two meth oxy groups bonded to that same carbon atom. Okay, and now we have two metal groups. Let's keep in mind that hydrolyzed is reversible and we want to use strongly acidic conditions. So we're going to indicate the presence of hydro ni um Now we may start with any of the two elk oxy groups. Let's suppose that we start with this one, the lumpy in oxygen will get protein ated. So we're going to capture a proton from hydro knee um followed by the formation of a water molecule. Here we get our protein, it'd intermediate. So you can say that here, we still have our meth oxy group and here we have our meth oxy group that is protein ated. Right? So we have that Haijun meaning there must be formal positive charge on auction because oxygen forms three bonds. And because auction has a formal positive charge, it's really easy to get rid of methanol from our structure because there's a lone pair on the adjacent auction atom that can be used in the formation of a pi bonds. Were forming a pi bond and we're getting rid of a methanol molecule. So let's draw the products and you may notice that this already gives us one of our products. So that would be our methanol molecules. So ch 30. H. And have the remaining fragment essentially corresponds to two metal groups. Now we have double bonded oxygen which still has that metal group. So you can say that there is still this siege three oxygen would have a formal policy of charge because once again it forms three bonds. And from here it's important to think about our next step. So the next step, the water molecule formed in the first step will essentially attack the electra Felix center of the carbondale group. So we're going to use water. The lone pair on oxygen would attack. We would break our pi bon. And here we are getting our next intermediate. Now you may notice that the next intermediate will have that central carbon atom With two methyl groups. Now here we are forming OH two. Right, we are going to expand our hydrogen oxygen would once again have a formal positive charge. But here we have our single bonded oxygen so that B O ch three. Right? So we have to think about the next step. In the next step, we're going to simply D protein, eight hour oxygen using another molecule of water. So what are comes in and the protein is said. So, we are capturing that proton and we are forming our hemi acid. All right, this is exactly what we were referring to whenever we have one meth oxy group or basically one elk oxy group in general. And then one alcohol group in your structure. That corresponds to a hemi acid. Also, this is where we get our hemi a saddle, our oh age group and our meth oxy group. Now from here, let's think about our next step. The next step is basically the repetition of what we had before we're going to protein ate our remaining meth oxy group. So we have our lone parent oxygen. It will basically a tag that proton in hydro ni. Um We're capturing that proton were forming a water molecule from here. And let's draw the protein ated intermediate. Right? We're going to add oxygen hydrogen bond. There's that formal positive charge on oxygen because it has three bonds. And now we essentially want to think about what we did before. We said that, okay, because there's a long pair on that adjacent oxygen, we can form a pi bon and get rid of another molecule of methanol. So that's exactly the same thing that we observed before. Let's show how that happens. The lone parent. This oxygen will be used in the formation of a pi bon, followed by the loss of methanol. In this part we are getting the following structures. First of all, we're getting an additional equivalent of methanol. So that's our second product. Even though it's not a unique product, it's exactly the same. But you get an additional equivalent of it formed. So you can say that okay here we get another molecule of methanol. Let's label this as our additional answer. We have to keep that in mind because we get it again and now the next structure would correspond to our protein ated intermediate. So that would correspond to two metal groups. Double bonded oxygen that is still protein ateD. And now the world last step is to d protein ate it. We said that we can use another molecule of water that would act as a base and the lone parent oxygen was just captured that proton and form our ketone. That's how we get our third final product because it cannot be hydrolyzed further so we can just throw acetone. Okay, so let's label our products. We have three products but actually two of them are exactly the same. We can just stay that. In a general case, if you want to list our products, they would correspond to the following. We would have our acetone plus to most of methanol. So these are our two products. Let's label our final answer in riot. Okay, so basically that will be our final answer. We just used the ideas from the mechanism and we said that the final answer would correspond to two different products one mole of stone, two moles of methanol. And in addition to that, going back to our original analysis, we said that the functional group in the starting material was accidental. And based on these answers, we may conclude that the correct answer is the multiple choice question is C However, if you have any questions, don't hesitate, leave your comment down below. Thank you for watching

For each compound,
1. name the functional group.
2. show what compound(s) result from complete hydrolysis.
(a)

Key Concepts

Functional Groups

Hydrolysis

Imines and Enamines

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