Hemiacetal - Video Tutorials & Practice Problems

General Features

In this next page, we're going to discuss one of the products that happens when a neutral alcohol attacks a carbonyl, and that's called hemiacetals. Let's just start off with one big disclaimer. That disclaimer is that technically the word "acetal" is used to describe the product of an alcohol and an aldehyde, while the word "ketal" is used to describe an alcohol and a ketone. However, it turns out that professors are lazy. Even textbooks are lazy, and they prefer since aldehydes and ketones are essentially the same molecule in terms of their reactivity, and nucleophilic addition is identical. Instead of using the distinction of acetal, ketal, hemiacetal, hemiketal, instead of saying all that, we're just going to use the acetal version. Whenever you see one of these gem diether products because notice that the end product of an acetal reaction is that they have 2 ether groups. They're in the geminal position. They're geminal. Whenever you have this, we're not going to worry about the R group so much. We're not going to worry was it originally an aldehyde or a ketone. I don't really care. I'm just going to call it an acetal even though technically it might be a ketal. But it's really like an industry standard thing where professors are not specific about the difference between an acetal and a ketal. If your professor specifically always makes that distinction, then by all means, go with what they're saying. But I'm just letting you know that even online homeworks and a lot of textbooks don't really care about the difference between acetal and ketal. You guys should know this by now. Hemiacetals are only stable when they are cyclic or when they're in a ring form. Here I have another picture of a cyclic hemiacetal. Notice that I have a central carbon that has the 4 groups that I'm looking for. Notice that what is a hemiacetal? A hemiacetal is a functional group with either 2 R's or 2 H's or a mix. It doesn't matter. And an OH and an OR in a geminal position, so an alcohol and an ether in a geminal position. That's a hemiacetal. Notice that this molecule is also a hemiacetal because I've got my H. I've got my R. I've got my OH, my alcohol, and my ether, my OR. When it's a cyclic hemiacetal, you're stable. But if it's not cyclic, then you're not going to be able to end up at the hemiacetal. Let me show you guys the general overview of this reaction. It turns out that when you react a carbonyl with one equivalent of alcohol, you're going to get what we call a hemiacetal. When you react it with the second equivalent of alcohol, it's going to be called an acetal, and it's going to make that geminal diether. The mechanism for the first step and for the second step is almost identical. The only way to really get it to stop at the hemiacetal is to make that cyclic version because if it’s not cyclic, it's just going to pass straight through the hemiac

Acid-Catalzed Mechanism

Another disclaimer before we begin. The mechanism that I'm about to show you contains a resonance structure as you can see here. We're going to fill this one out. I like to add resonance structures into my mechanisms because I think it makes it more clear where the arrows are being moved to. The only thing is that your professor may not use a resonance structure. Your professor just might decide to push the arrows without it. If that happens, it's okay. You can draw it his way, her way. You can draw it my way. It doesn't matter because in the end of the day, as long as the arrows are going to the same places, it doesn't matter if you add a resonance structure or not. This is going to be true with a lot of the mechanisms in clutch prep. I go out of my way to try to make the mechanisms extra clear and your professor might not really be explaining every arrow. Feel free to draw it my way even if it's slightly different than the way your professor drew it. Just know that the arrows are being pushed the same way in the end, so it's okay that you draw my mechanism which should be equivalent to the one your professor is drawing.

That being said, why don't you help me out with what the first step of this mechanism is? Since it's acid catalyzed, what's the very first thing we should be doing? Protonation. The very first thing we're going to do in an acid catalyzed mechanism is protonate. Notice that my acid in this case is a protonated version of alcohol. What I'm essentially using is ROH2+. You could have used any acid source. It doesn't have to be that. You could have used H+. You could have used H3O+. I'm just doing it like this because then the conjugate is going to make more sense for you guys, the conjugate base. But you could use any other acid source. What that's going to make is a resonance structure because I'm going to get a positively charged oxygen. But we know that this double bond could join the oxygen to make a lone pair and then I would get a formal charge on the carbon. I like drawing this resonance structure because it makes it clear to me that that carbon is now very electrophilic, even more electrophilic than it was when it was unreacted. Notice that the whole point of the acid catalyst is to make this carbon even more reactive than it was before, so reactive in fact that alcohol is going to want to attack it. That's the next step guys. The next step is what we call nucleophilic attack. I'm just going to put NA, nucleophilic attack. Nucleophilic attack is going to attach the O, make a new single bond and we're going to get a protonated version of an ether attached to that central carbon.

What do you think the next step is guys? Deprotonation. We have to regenerate that catalyst. I'm going to take my alcohol, my neutral alcohol. Since I started with an alcohol acid catalyst, I need to regenerate it. Then I would just grab the H and lo and behold, what do I have at the end? Now I have my O, my OR, my H, and my H. On top of that, I have my catalyst still there. Awesome guys. That is a hemiacetal. I always like to draw it in this cross structure because I like to always keep it consistent in terms of what I'm looking at, so that when I try to recognize the function group later, I always just put it into that cross and I'm like do I have all the groups that I need? Just a little peculiarity of mine. Anyway, that was the acid catalyzed mechanism to get to a hemiacetal. Not bad at all. Now are we going to stay there? No. Because this hemiacetal is not cyclic the way I drew it. This hemiacetal is either going to go back to the original carbonyl or it's going to keep reacting with alcohol to get to an acetal. More on that later. Now in this next video, I want to show you guys the base catalyzed version of the same reaction.

Base-Catalyzed Mechanism

As an overarching principle of carbonyl chemistry, the base-catalyzed mechanisms for reactions are almost always going to be easier than the acid-catalyzed ones. The reason is that in acid catalysis, we're trying to protonate, deprotonate to make things reactive. For base-catalyzed mechanisms, the reagent is already going to start off reactive because you're making it a strong nucleophile. Specifically for ketones and aldehydes, we know that strong nucleophiles can perform nucleophilic addition. That just means that this reaction here that I'm going to show you is just a nucleophilic addition reaction. What happens is my nucleophile is OR^-. Why? Because alcohol in the presence of a base, remember this is base-catalyzed, is going to react with the base to give me an oxide, OR^-. That oxide, since it's a negatively charged nucleophile, can perform nucleophilic addition on its own just like any other negatively charged nucleophile we've worked with. I would go ahead, attack the carbonyl carbon, make my tetrahedral intermediate, and I've got that O^- I have to take care of. But that O^- can protonate with the conjugate acid of my base or of my nucleophile. Then I could just grab one of the H's to regenerate the base that I would have lost in the other prior reactions. Then what I would wind up getting is I would get my hemiacetal again. I have my OH on one side, my OR on another, my H, my H, and I've got some OR left over that can react with another carbonyl. Guys, I hope that made sense. This one's a whole lot easier than acid-catalyzed. Let's move on to what happens in the second step, which would be acetals.