Predict the major products of the following reactions.
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Question

Predict the major products of the following reactions.

(j)

Accepted Answer

Hey everyone and welcome back draw the structures of the major products expected from the reactions given below. And we noticed that the starting material has an AL to hide group. Right? We have our Aldo hide group and we have our amino group. We're essentially treating this compound with a strong asset. We call that whenever Aldo heights and ketones react with amino compounds in particular supposed primary means we can form a means and let's see how that happens. So in the world first step of this reaction, we are going to read drool our starting materials. We can look at the steps of the mechanism. Now this is our Aldo hide group. Let's draw our I mean our substitution and because we're using a strong acid, we are going to perform our protein nation step. The lone parent oxygen captures the proton from the acid. And essentially we can just copy our fragment. For simplicity we may read drool our arrow and say that this is where we are adding our asset. And you may notice how oxygen gets protein ated. So we are going to have ohh, oxygen would have a formal positive charge because now it has three bonds in the next step because the electra Felix center can now be easily attacked. The fact that if you think about resonance stabilization, you can essentially break that pipe on and you will have a formal positive charge on carbon. So the electro Felicity of the center has increased the lone pair on nitrogen can be used in the attack. So basically we have an attack the electrolytic position and then we are breaking our pi bon by transferring the electrons onto oxygen, notice how we will actually be forming a ring. And to visualize it easily, we can just label our members within that ring. So this is the first carbon atom. This is our nitrogen. Now nitrogen will be bonded to this carbon atom. So that that's the third one. Then we have the fourth one and the fifth one, we will have a five member ring where one of the atoms is nitrogen. So that means if we draw the result on structure, let's see how it looks like we have our five member grain. Now we control another five member grain and now we have to be very careful. Let's think about the linkage. So that's our 1st 2nd atom. And now this second atom. Or basically position number three if we refer to our previous sketch. So that's our carbon number four. Carbon number three will be bonded to nitrogen. We're going to add add nitrogen over here. And now nitrogen in turn is bonded to one carbon atom at position number one. So let's add that position. Number one, Position number one is bonded to position number five within the other ring. Now let's think about our bonding as well. First of all this, nitrogen had two hydrogen atoms. So we're going to draw these two hydrogen atoms and hygiene has four bonds. So it must have a formal positive charge. Now at position three based on our numbering system, we understand that we will have that. Oh, age group. Okay, well done now. What we want to do from here. We essentially want to make sure that we d protein eight NH two. Right? Because it has a formal positive charge. So we can actually remove one of these two protons. And to do that, we are essentially going to use water. Right? We used our strong asset which corresponds to H 30. Plus. We use a shorthand abbreviation for H plus. And essentially we have the loss of a water molecule which can act as a base now. So water well essentially take one of these protons. We are going to transfer these electrons in the form of a lone parent nitrogen. And this is where we get our next structure. So let's draw it out. Okay and then we're going to modify our bonds but as we said before, we are going to remove one of our hydrogen. So basically you can just think of this as an age group. Okay, so we have our an age group and then from here we can think of our next step. So if we are dealing with strong listed conditions we can protein it oxygen once again. Right, so the lone parent oxygen can be protein ated by another equivalent of hydro ni um we can essentially draw the protein ated intermediate from here. And simply what we want to do is just add an additional hygiene to that oxygen. So that would be, oh, age two because we have added an additional proton, we will have a formal positive charge on oxygen. And now from here because oxygen has a formal positive charge, we have a good leaving group. We can form a water molecule. The lone pair on nitrogen can be used in the formation of that pi bond. Which will give us I mean, so we are forming our pi bond fold by the loss of the leaving group. And this will actually first of all form a protein ated intermediate. So we will need an extra step but we almost understand that we have arrived at the final product. So let's see how that looks like. So let's get rid of water. Right? We had the loss of water. And now for this step, we said, okay, if nitrogen is using its lone pair in the formation of a pi bon, let's just draw that pi bon because nitrogen once again has four bonds, we want to make sure that we include that formal positive charge in nitrogen and that we remove that hydrogen using another molecule of water. So we're going to use water once again take that proton transfer these electrons onto nitrogen. And this gives us our final product. So you can essentially draw it out, let's fix it based on our previous structure. So we don't have any high gens anymore. Ni jin already has three bonds. There's a long para nitrogen. We have formed a long pair using this arrow. So this will be our final product based on the identity of this product, which we essentially are going to label in green. So that's our product. We can state that the correct answer to the multiple choice question is a. However, if you have any questions, don't hesitate. Leave a comment down below. Thank you for watching.

Predict the major products of the following reactions.
(j)

Key Concepts

Aldehyde Reactivity

Amine Nucleophilicity

Acid-Catalyzed Reactions

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