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Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 6, Problem 29a

A reluctant first-order substrate can be forced to ionize by adding some silver nitrate (one of the few soluble silver salts) to the reaction. Silver ion reacts with the halogen to form a silver halide (a highly exothermic reaction), generating the cation of the alkyl group.

Give mechanisms for the following silver-promoted rearrangements.
(a)

Verified step by step guidance
1
Step 1: Recognize that the reaction involves silver nitrate (AgNO3) in water, which promotes the ionization of the alkyl halide (R-X). The silver ion (Ag+) reacts with the halogen (Iodine in this case) to form a silver halide precipitate (AgI↓), leaving behind a carbocation (R+).
Step 2: Identify the substrate. The starting compound is a tertiary alkyl iodide, (CH3)3C-CH2-I. The tertiary carbon is highly stable and will form a carbocation upon ionization.
Step 3: The iodide ion (I-) is removed by Ag+, forming AgI↓. This generates a tertiary carbocation at the (CH3)3C-CH2 position.
Step 4: Water (H2O) acts as a nucleophile and attacks the carbocation, leading to the formation of an alcohol group (-OH) at the carbocation site.
Step 5: The final product is (CH3)3C-CH2-OH, where the iodine atom has been replaced by a hydroxyl group (-OH). This substitution occurs via an SN1 mechanism, facilitated by the silver nitrate and water.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

First-Order Substrate

A first-order substrate refers to a molecule that undergoes a unimolecular nucleophilic substitution (S_N1) reaction, where the rate of reaction depends solely on the concentration of the substrate. In this context, the substrate is typically an alkyl halide that can ionize to form a carbocation. Understanding the stability of the carbocation formed is crucial, as more stable carbocations will favor the reaction.
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Silver Nitrate Reaction

Silver nitrate (AgNO3) is used in organic chemistry to promote the ionization of halides by forming insoluble silver halides (AgX). The silver ion (Ag+) reacts with the halogen atom (X) in the substrate, facilitating the departure of the halide and generating a carbocation. This reaction is highly exothermic and is a key step in forcing reluctant substrates to undergo rearrangements.
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Carbocation Rearrangement

Carbocation rearrangement is a process where a carbocation undergoes structural changes to form a more stable ion. This can involve hydride shifts or alkyl shifts, leading to the formation of tertiary carbocations from secondary or primary ones. Understanding the mechanisms of these rearrangements is essential for predicting the products of reactions involving first-order substrates and silver nitrate.
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Related Practice
Textbook Question

A reluctant first-order substrate can be forced to ionize by adding some silver nitrate (one of the few soluble silver salts) to the reaction. Silver ion reacts with the halogen to form a silver halide (a highly exothermic reaction), generating the cation of the alkyl group.

Give mechanisms for the following silver-promoted rearrangements.

(b)

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Textbook Question

Show how you would convert (in one or two steps) 1-phenylpropane to the three products shown below. In each case, explain what unwanted reactions might produce undesirable impurities in the product.

744
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Textbook Question

Under certain conditions, when (R)-2-bromobutane is heated with water, the SN1 substitution proceeds twice as fast as the SN2. Calculate the e.e. and the specific rotation expected for the product. The specific rotation of (R)-butan-2-ol is −13.5°. Assume that the SN1 gives equal amounts of the two enantiomers.

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Textbook Question

For each reaction, give the expected substitution product, and predict whether the ­mechanism will be predominantly first order (SN1) or second order (SN2).

d. cyclohexylbromide + methanol

e. cyclohexylbromide + sodium ethoxide

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Textbook Question

Show how you would convert (in one or two steps) 1-phenylpropane to the three products shown below. In each case, explain what unwanted reactions might produce undesirable impurities in the product.

1009
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Textbook Question

For each reaction, give the expected substitution product, and predict whether the ­mechanism will be predominantly first order (SN1) or second order (SN2).

c. 1-iodo-1-methylcyclohexane + ethanol

763
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