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Ch.5 - Stereochemistry
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 5, Problem 53e,f

Draw a three-dimensional structure for each compound, and star all asymmetric carbon atoms. Draw the mirror for each structure, and state whether you have drawn a pair of enantiomers or just the same molecule twice. Build molecular models of any of these examples that seem difficult to you.
(e) chlorocyclohexane
(f) cis-1,2-dichlorocyclobutane

Verified step by step guidance
1
Step 1: For chlorocyclohexane, start by drawing a cyclohexane ring in its chair conformation. Add a chlorine atom to one of the carbon atoms in the ring. Ensure the chlorine atom is either in the axial or equatorial position to represent the three-dimensional structure.
Step 2: Identify any asymmetric carbon atoms in chlorocyclohexane. An asymmetric carbon is one that is bonded to four different groups. Star any asymmetric carbons in the structure.
Step 3: Draw the mirror image of chlorocyclohexane by reflecting the positions of the chlorine atom and other substituents. Compare the original structure and its mirror image to determine if they are enantiomers (non-superimposable mirror images) or the same molecule.
Step 4: For cis-1,2-dichlorocyclobutane, draw a cyclobutane ring and place two chlorine atoms on adjacent carbons. Ensure both chlorine atoms are on the same side of the ring (cis configuration). Represent the three-dimensional structure clearly.
Step 5: Draw the mirror image of cis-1,2-dichlorocyclobutane by reflecting the positions of the chlorine atoms and other substituents. Compare the original structure and its mirror image to determine if they are enantiomers or the same molecule. Star any asymmetric carbons in the structure.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Asymmetric Carbon Atoms

Asymmetric carbon atoms, or chiral centers, are carbon atoms that are bonded to four different substituents. This unique arrangement allows for the existence of two non-superimposable mirror images, known as enantiomers. Identifying these centers is crucial for understanding the stereochemistry of a molecule, as they determine the molecule's optical activity and its interactions with other chiral substances.
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Enantiomers

Enantiomers are a type of stereoisomer that are mirror images of each other but cannot be superimposed. They have identical physical properties in an achiral environment but can exhibit different behaviors in chiral environments, such as biological systems. Recognizing whether two structures represent enantiomers is essential for predicting their chemical behavior and interactions.
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Cis-Trans Isomerism

Cis-trans isomerism, also known as geometric isomerism, occurs in compounds with restricted rotation around a double bond or a ring structure. In cis isomers, substituents are on the same side, while in trans isomers, they are on opposite sides. This concept is particularly relevant in cyclic compounds like cyclobutane, as it influences the molecule's shape and reactivity, impacting its stereochemical properties.
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Related Practice
Textbook Question

The original definition of meso is 'an achiral compound that has chiral diastereomers.' Our working definition of meso is 'an achiral compound that has chiral centers (usually asymmetric carbon atoms).' The working definition is much easier to apply, because we don't have to envision all possible chiral diastereomers of the compound. Still, the working definition is not quite as complete as the original definition.

a. Show how cis-cyclooctene is defined as a meso compound under the original definition, but not under our working definition. (Review Figure 5-19)

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Textbook Question

3,4-Dimethylpent-1-ene has the formula CH2=CH—CH(CH3)—CH(CH3)2. When pure (R)-3,4-dimethylpent-1-ene is treated with hydrogen over a platinum catalyst, the product is (S)-2,3-dimethylpentane.

d. How useful is the (R) or (S) designation for predicting the sign of an optical rotation? Can you predict the sign of the rotation of the reactant? Of the product? (Hint from Juliet Capulet: “What’s in a name? That which we call a rose/By any other name would smell as sweet.”)

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Textbook Question

A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active.

c. If this reaction could be accomplished using H2 and a nickel catalyst, would the product be optically active? Explain.

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