Show how you would synthesize octanal from each compound. You ...

Question

Show how you would synthesize octanal from each compound. You may use any necessary reagents.

(b) non-1-ene

Accepted Answer

Hey everyone and welcome back in today's video, we are going to show how happy one in can be converted to hacks in l provide any necessary regions. First of all, let's draw Heft one in. That's our seven member chain with a double bond at position number one. So we're going to draw seven carbon atoms that B 1234567. And then we are adding a pi bond between carbons one and two. According to the problem, we are going to form hexagonal out of it. And hexagonal essentially implies there will be six carbon atoms 123456. And carbon number six would essentially contain and Aldo hide group because we have hexagonal, right? So we're going to add our carbonell group and hydrogen atoms. So that corresponds to an AL to hide. Now we want to look at this reaction and understand the net change that took place in this reaction. First of all notice how we had seven carbon atoms. Right? So we can say that seven carbon atoms over here and for the right structure, we have six carbon atoms. Okay, so let's label C as capital C. So we can clearly see that we're referring to carbon atoms. So we're going from seven carbon atoms to six carbon atoms. We are losing one carbon atom and in addition to that, we are going from an elk een to an AL to hide. Right? So this implies we have oxidative cleavage of an elk een essentially. You're shortening the chain, You're getting rid of this part and you're producing an AL to hide out of it. Let's recall one of the ways to perform an oxidative cleavage which is called owes analysis in the general form. Whenever you have an L. Keen, let's start by drawing a double bond. And let's suppose you have several different substitutions such as R one, R. T. And then for clarity, let's put that here, we have hydrogen instead of an alcohol substitute mint. And then some alcohol substitution are three in an analysis reaction, which requires the following set of regions reaction number one edition of ozone at a were low temperature negative 78 degrees Celsius followed by addition of dimethyl sulfide in water, we are essentially going to break our carbon carbon double bond, we will get to fragments. So if we start with the bottom one, we can say that the bottom one with essentially contain that part of the double bond. Right? There is no more carbon here. Let's keep that in mind. But we're just going to draw our three because it's bonded to that carbon. And then hydrogen on the other hand. Now, because we broke the structure, we have another fragment. So we are going to start with that fragment of the original double bond and at R one and R two D. Two that we R one and R two. Now because it's oxidative cleavage. We're just going to add oxygen to each end of our result on fragments. So we're going to add oxygen over here at that double bond. And here, so we get our to carbondale compounds. One of them is an al hide. One of them is a key tone. But the most important thing to understand is that we're breaking our double bond and we're adding oxygen atom to each end. Now this would really work for us. Let's see how that happens. So if you look at our L king, we have heft one in, we can draw it out once again, 1234567. We have our double bond. If we perform this reaction for simplicity, let's say if we perform an ozone hole is this reaction? We're going to break that double bond and we have to think about the products that we form. And let's see if that would work for us. Indeed, we're getting rid of one carbon atom. So it looks like we're on the right track. Let's keep in mind that here we have our implicit hydrogen and there are two implicit hye jin's over here. So we get to products, let's start from the left part. We are going to throw six carbon atoms because we have left. So we're going to have 123456. Notice how this carbon atom has hydrogen. And then here we will have the fragment of our original double bond. We want to make sure that we are adding oxygen to it just as we did before and then the other structure that we're getting would correspond to our double bond to hydrogen atoms. And then we simply need to add oxygen. So we get to products and indeed one of them is hexen L. 123456 carbon atoms. Our Aldo hide group exactly what we wanted. That's our hexen L. So we have our answer. We understand that this reaction requires those analysis step number one ozone at negative 78 degrees Celsius, step number two addition of the metal sulfide in water. That's how reductive work up. And we can label these regions as our final answer because for this synthesis to convert helped one in our starting material to hexen L. We need to perform an analysis reaction which requires us to use ozone followed by dimethyl sulfide in water. The correct answer choice to the multiple choice question is a However, if you have any questions, don't hesitate to leave a comment down below. Thank you for watching

Show how you would synthesize octanal from each compound. You may use any necessary reagents.
(b) non-1-ene

Key Concepts

Alkene Reactions

Oxidation and Reduction

Functional Group Interconversion

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