Which of the following structures corresponds to a molecule with molecular formula $C_3{H}_{4}O$ that contains both an alkyne and an ether functional group?

• A. $\mathrm{CH}\equiv C-O-\mathrm{CH}{3}_{}$
• B. $\mathrm{CH}{3}_{}-C\equiv C-\mathrm{OH}$
• C. $\mathrm{CH}{2}_{}=\mathrm{CH}-O-\mathrm{CH}{3}_{}$
• D. $\mathrm{CH}{3}_{}-O-\mathrm{CH}{2}_{}\mathrm{CH}{3}_{}$

Answer: (A)

Verified step by step guidance

1. Identify the molecular formula given: \(C_3H_4O\). This means the molecule contains 3 carbon atoms, 4 hydrogen atoms, and 1 oxygen atom.
2. Recall the functional groups involved: an alkyne contains a carbon-carbon triple bond (\(C \equiv C\)), and an ether contains an oxygen atom connected to two carbon atoms (\(C - O - C\)).
3. Analyze each given structure to check for the presence of both an alkyne and an ether group. The alkyne must have a \(C \equiv C\) bond, and the ether must have an oxygen atom bonded to two carbons without any hydrogen attached to oxygen (which would indicate an alcohol).
4. Verify that the total number of carbons, hydrogens, and oxygens in the structure matches the molecular formula \(C_3H_4O\). Count each atom carefully to ensure the formula fits.
5. Select the structure that satisfies all criteria: contains a \(C \equiv C\) triple bond, an ether linkage (\(C - O - C\)), and matches the molecular formula \(C_3H_4O\).