Which of the following compounds is aromatic according to Hückel's rule ($4n+2$ π electrons)?

• A. Cyclohexane ($C_6{H}_{12}$)
• B. Benzene ($C_6{H}_6$)
• C. Cyclooctatetraene ($C_8{H}_8$)
• D. Cyclobutadiene ($C_4{H}_4$)

Answer: (B)

Verified step by step guidance

1. Recall that Hückel's rule states a compound is aromatic if it is cyclic, planar, fully conjugated, and contains \$4n + 2\( π electrons, where \)n$ is a non-negative integer (0, 1, 2, ...).
2. Analyze each compound to determine if it meets the criteria: it must be cyclic, planar, and have a continuous overlap of p orbitals (fully conjugated system).
3. Count the number of π electrons in each compound: for example, benzene has 6 π electrons from its three double bonds, cyclobutadiene has 4 π electrons, and cyclooctatetraene has 8 π electrons.
4. Apply Hückel's formula \$4n + 2 = \text{number of π electrons}\( to each compound to see if the number of π electrons fits the rule for some integer \)n$.
5. Identify which compound satisfies all conditions (planarity, conjugation) and has a number of π electrons fitting \$4n + 2$; this compound is aromatic according to Hückel's rule.