Draw the structure of each compound.
(a) o-nit...

Question

Draw the structure of each compound.

(a) o-nitroanisole

(b) 2,4-dimethoxyphenol

(c) p-aminobenzoic acid

Accepted Answer

Hey everyone and welcome back in today's video, we are going to write the corresponding structure for each of the names shown below. Number one M. Nitro an ISo number 22 comma three D. Math, oxy fennel and number three M amino benzoate acid. Now let's start with the first one. Whenever we want to give a structure to a particular name, we generally read it from right to left. In other words, we want to extract the most important information regarding our parent because when we know our parents, we can easily assign the remaining substitutions. First of all, it says M nitrogen is also we read it from right to left. The first bit of information is that we have an ISO as our parent. Let's recall that an is all consists of a benzene ring and that benzene ring contains a meth oxy substitution. So basically we're going to add meth oxy two at O C three oxygen bonded to the metal group. So that's an esol. And we understand that this is our parent meaning something else in the name will essentially correspond to our substitution. And we noticed that the remaining bit of information is that it's nitrile. To begin with. We are just going to analyze nitro and we have to recall that the nitro substitution is based like N. 02. Now that that means one of the carbon atoms within our ring will correspond to will actually be bonded to a nitro group N 02. That's our nitro. And to understand which carbon exactly. We have to keep in mind that this is M nitro we call that M means Mata, so that's meta position. We are essentially going to add it either here or here. It doesn't matter because this is our substitution. And you may keep in mind that whenever we have our benzene ring, this is our Ortho position, right to Ortho positions. Then we have two meta positions And then the remaining one is para. So because it's as M or meta, that's just a shorthand notation. We already understand that we are going to bond and to group at this position. So we are just going to draw our file structure. This is how it's done. So we get our end goal, we start by drawing benzene, we add meth oxy substitution. This is how we get an insole. And then because of the meta position we have a nitro substitution. We just look at the meta position either here or here. And let's suppose that we choose this meta position. Once again in this matter because we have a line of symmetry and then we add our nitro substitution. So this is how we get the first structure. Let's label, this is our partial answer. Moving on to # two, we first of all read the structure from right to left and if we read it from right to left, we notice 1st, 1st of all just read it normal that B two comma three, diamond Toxie fennel. So if we read it from right to left, the most support part of information is that this is final. So our parent is fennel. Now if our parent is final, we just recall that fennel is benzene with an alcohol group bonded sit so we can add in a wage group and this is fennel because number one goes to an a wage group. Right? The main substitution in our parents, we can essentially enumerate our ring either clockwise or counterclockwise. It doesn't really matter. So let's suppose that we go clockwise and then we say that this would be carbon number two. This would be 345 and six according to the name we got to know now what else we have here is that we have diamond Toxie die correspond to prefix. And the reason why we're using this prefix is because the the two substations are equivalent. So di means two And these two are at positions two and three rights. We have two equivalent substitutions at positions two and 3. And those substations are meth oxy recall that meth oxy is an elk oxy substitution. So that means we have oxygen bonded to some al kill group. Right? And in this case that's metal. So oxygen bonded to metal. That's her meth oxy group meaning if there are two meth oxy substitutions at positions two and three. We are just going to add to myth oxy groups over here and here we are done. We are ready to draw the final structure that will be fennel. So we are going to draw benzene with an O. H group And then at positions two and We are going to add to meth oxy substitue ints. So OC three oh ch three, That will be our final structure. So let's label this as another answer to our multiple part problem. And we are ready to move on to number three for number three. As the name suggests, we have M amino benzoate acid because at the working end it says ben's OIC acid, we have to recall that any benzo weak acid involves the presence of benzene. And we are essentially bonding a car book silic acid group so that B C 00 H and that's benzoate acid. However, at the beginning it says M amino. We already know that M means meta and now amino group implies that you have a bond between your one of your carbon atoms and NH two group AMINO is an NH two group. Right? So we will have this substitution at the meta position. We already know our positions. That's Ortho and Ortho meta and meta and ampara. Once again, there's a line of symmetry, it doesn't matter which position you choose between the two matter, right? Because we need the meta position. We have two possibilities whether you added here or here. That's the same thing because the two positions are equivalent meta positions. So let's suppose that we choose this one and that essentially allows us to draw the final structure. We are going to draw benzoate acid and then at the meta position. Over here we are going to attach an amino group, which is N H two. Let's label this as our final answer because now we have all of the three structures and based on the identity of the structures, we can conclude that the correct answer to this multiple choice question is to be However, if you have any questions, don't have states, leave a comment down below. Thank you for watching.

Draw the structure of each compound.
(a) o-nitroanisole
(b) 2,4-dimethoxyphenol
(c) p-aminobenzoic acid

Key Concepts

Aromatic Compounds

Substituent Effects

Functional Groups

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