Name the following compounds:
(a)

Question

Name the following compounds:

(a)

(b)

(c)

Accepted Answer

Hey everyone and welcome back in today's video, we are going to give the appropriate name for each of the compounds shown below, not just how three compounds have benzene rings and definitely benzene ring is going to be our parent in each case because essentially whenever we have a ring and several substitutions which are significantly small and notice how we have a car books telecast group, a bromo substitution with oxy nitro and chloral. They're significantly small substations and our parents must have a larger number of carbon atoms. So in each case benzene will be our parent and we have several benzene derivatives. Let's start with the first one and let's think about the steps needed to name the structure. First of all, if benzene is our parents, we understand that benzene will be at the very end of our name and we are going to identify the substitutions bondage that benzene ring, you may see that there are two chlorine atoms and you may recall that whenever we have chlorine bonded to a carbon, that would be a chloral substitution. Right? We are going to use oh, as our suffix. So we have two chloral substitution ints because we have to, we are going to use a prefix of di indicating that there are two chloral substitution ints and now the world last thing we need to do is just to enumerate our parents whenever we have to substitute wants the best idea is to start with the first one, it doesn't matter which one you use because there are equivalent to each other. We don't need to worry about the alphabetical order. We can essentially state that this chlorine as position dis chlorine is bound into position number one. And then if we go clockwise. And the reason why we're going clockwise is because if we go counterclockwise, that's a longer path for us to get that chlorine and that would give us a higher coefficient for chlorine. Instead we're going a shorter route which gives us 23. Right? So this is position number three. Otherwise you would get if you went counterclockwise that'd be 12345. Right? We don't want to have one comma five because we want to make sure that the coefficients are as minimal as possible. So we now understand that positions one and three contain two chloral substitutions. Our parent is Benzene. Let's combine all of this information into a single name. Whenever we give a name we start with the positions of our substitutions we can say 1:03. Right? Those are the positions of the two substitutions. This is followed by the prefix because we have two of them were going to die, then die is followed by the name of these substitutes. They are chloral substitutions. So we are going to say chloral and then our parents as Benzene who are going to say benzene and that finishes that. The name would be one comma three. Di chloral Benzine. So let's label this is our answer to number one. We have got our name And Lisbon wants the 2nd 1. The second one is a bit different because you have your parents which is Benzene so far. But we have two different substations. One of them is a nitro substitution. Notice how we have N 02 and the name of N 02 as a substitution is our nitro group and the other one is meth oxy oxygen bonded to a metal group. That's our ether group. So we can say the actual name is meth oxy. Now its name it properly, we first of all once understand which of these has a higher priority. And you may recall that nitrile group is a group which is which essentially corresponds to one of the lowest possible priorities myth, oxy corresponds and ether and any ether is slightly higher in priority than nitro group. So ether gets a higher priority meaning our parent. Besides being just benzene includes the meth oxy group itself so we can draw it. And now this would be our actual parent because it incorporates the highest where you are the group. Now you may recall that whenever meth oxy group is bonded to the Benzene ring, we call it an is all. So now that we realize that this is our parents, we just need to understand what kind of substitution we have, as we already said, this is our nitrile group and this is the only substitution now. So if the highest priority gets number one, the only way for us to minimize the coefficient of our substitution is to go counterclockwise that will give us the adjacent position position. Number two. And this is how we get our name which is two. We start with the number that corresponds to our substitute print. No prefixes are used because it's the only substitute print. Then we give it a name and we say nitro. And because we are done with our substitutions, we name the parent which is an is all And therefore the name is to Nitro and is all. Let's label this is our final name for the structure and let's move on to the 3rd 1. Now for the 3rd 1 we once again have a benzene ring with two different substitue ints one of them is a bromo group because we have these two bromine atoms and because we have two of them, we we already understand that we are going to use a prefix just as with it before so that would be died because we have two of them. We are not going to worry about the positions yet because we still have one more substitution which is our car book silic acid group. Right? We have our C 00 H. That's our car book silic acid. And once again because we have different types of substitutions, we want to understand the priorities. Recall that assets our highest in priority assets are higher in priority than any other group. So you can say anything including any halogen, right? So we can see including roman because assets are highest in priority. We understand that the curb oxalic acid will belong to the parents. So instead of just having benzene, we will have the following parent. That would be our benzene ring and our curb oxalic acid group. You may recall that whenever you have a benzene ring and a car book, sarcastic group, bonnets, yet we call this compound benzo weak acid. So that's our parent meaning we actually have only two bromo substitue ints. So if you recall we had them at these two positions And now position # one is at this carbon because the car bookseller casted group gets the highest priority and we simply have to two equivalent ways to enumerate our parents. We can go counterclockwise that we want to 34, 5 and six and we can go clockwise. That'd be 123456. Right? So in any case you get the same name, That would be two and 6 for the two bromo substitutions because the compound essentially has this line of symmetry. So we can say that the two bromo substitutions are at positions two and sex. And we are ready to give it a name because we have our substations positions multiplicity and the parent name. So now the name would be starting with our substitutions. That be two comma six. How many do we have die? The name of the substitution bromo the name of the parent benzoate acid. So the name for this structure would be two comma six dye bromo benzoate acid. So we got we got all of our names. One comma three die chloral benzine for the first one to nitro, and it's all for the second one and two comma six dye bromo benzoate acid for the third one. Based on these answers, we can conclude that the correct choice to this multiple choice question would be B However, if you have any questions, don't have states. Leave your comment down below. Thank you for watching.

Name the following compounds:
(a)
(b)
(c)

Key Concepts

Nomenclature of Aromatic Compounds

Substituent Effects

Ortho, Meta, and Para Positions

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