Give a systematic name and a common name (if it has one) for e...

Question

Give a systematic name and a common name (if it has one) for each of the following amines and indicate whether each is a primary, secondary, or tertiary amine:

e. Structural formula of a branched amine with two ethyl groups and one propyl group attached to a nitrogen atom.

Accepted Answer

Hey everyone, Let's solve this problem. It says right, appropriate systematic names for the structure shown below. Well, I immediately noticed that all of these groups have these nitrogen groups on them. So these are going to be a means. So let's recall a few things about a mean nomenclature. Firstly, a means modify the root name. They are not added before the root name. Like most substitue ints. So when they when we incorporate the amine into the root name, we're going to drop the e say at the end of butane or plantain and we're going to add the suffix amine. So sabe, you Tana mean or pantano mean? Okay. Also a means have priority with numbering over alcohol groups. So say instead of a methyl group, you'd rather number closer to the mean. And lastly if you have a secondary or tertiary mean, that's multiple carbon chains, potentially. Right. So you might be wondering how do I number this? Well, you still want to number the longest carbon chain, so that's not really changing. And the smaller chains that are also coming off the nitrogen can be labeled as in substitue ints. So instead of writing what number carbon they're coming off of, You just write that they're coming off of the nitrogen. Okay, so let's apply this to our compounds here. Starting with a well, I see that a secondary amine. Right. There are two carbon groups here. I'm going to number this, the longest carbon chain on this side, which will be 1234. Right. And when I'm numbering again, I want to be closest to the mean, starting. So I won't start on this side. That would make the amine on carbon three. I want it this way. So that the mean is on carbon too. So that will be butane, right? 1234 carbons. But remember we dropped the E and add the suffix amine utan I mean But we also have to include the location of the amine and we can either do that out front for two butane, amine or butin to amine. We'll just stick with butin to a mean. Okay, so now let's add the substitution groups. We have a chlorine atom on carbon three in a methyl group on the nitrogen. And we go in alphabetical order. So chlorine comes first we have three chlor oh and now that methyl group is coming off of end. So it's an end substitue ints. So we write N methyl and that's all the substitution. So now we write our root name here Butin too. I mean. Alright, so that's it for a is that making sense? Alright, so let's go to be. So this time we have a primary amine. Right? There's two hydrogen is only one carbon group. So we know we have two number somewhere over here and the longest carbon chain. Well we have this ethyl group 123. We have this ring 12345. Right? So that's definitely going to be our longest chain. So we're going to number the ring and again we want to start closest to the amine group. But which way are we going to go? Well, since the substitute prints would be on two and five either direction, we can use alphabetical order here to decide which one. So we have ethyl and methyl. So since ethel would come before methyl, when we're writing out the substitue ints, we can number it the ethyl as carbon too. Okay, so that's sort of a last resort. If it's going to be the same numbers two and five, either direction, you can go with alphabetical order. Okay, so there is our parent chain and our substitue ints are going to be that ethel in the methyl group. So let's write our root name Again. We have 12345. That's pent. But it's also a ring. So this will be cyclo plantain, but it's in a mean. So we take out the e add cyclo pent and where's the Amin on carbon number one? Oops, Pen Tan one, I mean, Okay, so that is our root name. Now let's add to ethel and five methyl. So again, the ethyl goes first. So we have two ethyl five metal cyclo pen tan one to me. So notice how we're sort of building it backwards. Right? We always start from the end the root name and we're adding substitue ints to the front except the amine. Right? That's the suffix. Alright, let's do our last compound. So we have another ring here. But this time we have a fennel With an NH two group and that is actually going to be the name anna Lynn. Okay, so that's a common name. We can use to describe this whole route. So if that is our whole route then we only have one substitue in here. The bro mean? And how would we number this? Well, again, we start closer to the amine group. So that would be one. And would I rather have bromine on carbon two or 6? Definitely carbon to write? We always want the lowest numbers for our substitue ints. So we go counterclockwise in this example. So we'll have two bromo aniline. Right? Our parent name is just an Allen here and then we're adding our substitution out front, just like the other problems. So we have an online and then adding our substitution out front to bromo. two Bromo Annalee. Okay, that's it for this problem. I hope this video is helpful and thanks for watching

Give a systematic name and a common name (if it has one) for each of the following amines and indicate whether each is a primary, secondary, or tertiary amine:
e.

Key Concepts

Amines

Systematic Naming

Common Names

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