For each compound,
1. name the functional group.

Question

For each compound,

1. name the functional group.

2. show what compound(s) result from complete hydrolysis.

(b)

Accepted Answer

Hey everyone and welcome back name the functional group present in the following compounds and show the products of their complete hydrolyzed sis. Let's begin by looking at the structure. The most important carbon that we have to look at is the central carbon atom. Its wanted 22 alcohol groups. Our alcohol groups. We have our alcohol and our elk oxy group. Right? We have our meth oxy group, bonnets, that carbon. So before we answer the first question, let's recall that there are two types of compounds that you want to distinguish and be extra careful. One of them supposing that we draw that central carbon atom would correspond to the following structure. Let's suppose that you have alcohol substations R one and R two. And suppose that here we have O. R. Three O. R. Four. Now this will be an acid a lot because we have two elk oxy groups bonded to the same carbon atom. But what if we change one of the elk oxy groups with an alcohol? Let's suppose that we change this O. R. Four. Then we end up with this with the following structure, R one, R two, O. R three. And here we have our alcohol. So now whenever we have an alc oxy group with an alcohol group that would give us hemi a saddle. So let's recap to Alcock see groups bonded to the same carbon. That will be a subtle one. Alcock see group one alcohol group bonds to the same carbon atom. That hemi a subtle and that's what we see here, we have one alcohol group. One elk oxy group, that's our meth oxy group. So this structure is a hemi a settle. Okay, well then we have the first answer to our problem. We just need to think about the complete hydrolyzed sis of this mes Adele. And to draw the products of the complete hydrolic sis. We are just going to redraw the original structure and we are going to recall that we need to use strongly as the conditions for this reaction to take place. Now what we're going to do, we are going to draw equilibrium arrows because hydrolyzed sis is reversible for hemi acid house and we are going to include H plus which indicates strongly acidic conditions. The first step is the protein nation step between the two. We're going to protein eight hour meth oxy group. It's essentially the auction atom here is more basic due to the fact that there's carbon atom adjacent to it instead of hydrogen that produces electrons auction is electron withdrawing through the electron density around the auction increases And therefore it is more basic because it's more basic. We're going to start with this lone pair. We're going to show that auction gets protein ated. Let's draw the structure of hydro ni um we have that proton capture the removal of the water molecule and now we are ready to try the protein eight is intermediate. So we still have our alcohol group. But now we have oxygen that is protein ated. We still have that metal group. So there must be a formal positive charge and oxygen because it forms three bonds. And from here we notice that because auction has a formal positive charge, it becomes a good leaving group. So we can get rid of a methanol molecule. So the lone pair on oxygen within the alcohol group cannot be used in the formation of a pi bond, followed by the loss of this structure which is methanol. This is how we get one of our products. Right? So we can ensure that one of our products is methanol ch 30. H. Let's label this as our first product and now then we still have our protein ated intermediate. So we are going to draw our five member ring. Now here we have our double bond oxygen which is still protein ated. And the world last step is actually to use that water molecule generated in the first step that can d protein ate the structure and we will get our key tone that will be it. So let's see how that works. Let's draw that water molecule H20. The lone parent oxygen would attack that proton and we would form the key tone. Let's include the equilibrium arrows and indicate that the second product formed in this complete hydrolyzed stop is cyclo penso known. Let's label it as our second product. And let's conclude our findings. So first of all, we were asked to name the functional group present in the given compound. And we said this was hemi as well. So that's our first answer. The reason why it's mes cells because there is an alcohol group and an Alcock C group bonded to the same carbon atom. Then we threw our hide releases products using the mechanism of a complete hydrolic sis of a hemi SDL. We said that we are going to protein eight hour Alcock C group first because there's a higher electron density and oxygen to the fact that carbon is donating electron city oxygen in a stronger way than hygiene is right. We have essentially our oxygen which has a high electro negativity. So it's withdrawing electrons from the metal group. And essentially that's why we're protein protein eating it first. Now, when it gets protein ated we can get read of methanol from our structure easily. Right? Because we have an adjacent oxygen that can form a pi bon. So here we get our first product that's methanol. And then when we get our protein ated intermediate, we're using another equivalent of water to essentially d protein ate it and produce our key tone that will be cyclo tension on. So we can label this as our second product hemi a settle the first answer to products in green. And based on our findings, we may conclude that the correct answer to the multiple choice question is d however, if you have any questions, don't hesitate to leave a comment down below, Thank you for watching.

For each compound,
1. name the functional group.
2. show what compound(s) result from complete hydrolysis.
(b)

Key Concepts

Functional Groups

Hydrolysis

Structural Representation of Organic Compounds

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