Which of the following compounds is the ester formed from the reaction of $\mathrm{CH}{3}_{}\mathrm{COOH}$ (acetic acid) and $\mathrm{CH}{3}_{}\mathrm{CH}{2}_{}\mathrm{CH}$₂OH (1-propanol)?

• A. $\mathrm{CH}{3}_{}\mathrm{COOCH}$₃ (methyl acetate)
• B. $\mathrm{CH}{3}_{}\mathrm{COOCH}{2}_{}\mathrm{CH}$₃ (ethyl acetate)
• C. $\mathrm{CH}{3}_{}\mathrm{COOCH}{2}_{}\mathrm{CH}{2}_{}\mathrm{CH}$₃ (propyl acetate)
• D. $\mathrm{CH}{3}_{}\mathrm{CH}$₂COOCH2CH₃ (propyl propanoate)

Answer: (C)

Verified step by step guidance

1. Identify the acid and the alcohol involved in the esterification reaction. Here, the acid is acetic acid (CH\3COOH) and the alcohol is 1-propanol (CH\3CH\2CH\2OH).
2. Recall that in ester formation, the hydroxyl group (-OH) from the carboxylic acid and a hydrogen (H) from the alcohol's hydroxyl group combine to form water, and the remaining parts join to form the ester.
3. Determine the alkyl group from the alcohol that will be attached to the oxygen in the ester. Since the alcohol is 1-propanol, the alkyl group is a propyl group (CH\3CH\2CH\2-).
4. Write the ester structure by combining the acyl part from acetic acid (CH\3CO-) with the propyl group from 1-propanol, resulting in CH\3COOCH\2CH\2CH\3.
5. Compare this structure with the given options to identify the correct ester, which is propyl acetate (CH\3COOCH\2CH\2CH\3).